(X-2)(x+1)=(x^2-38)-(x-6)(x+6)

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Solution for (X-2)(x+1)=(x^2-38)-(x-6)(x+6) equation: 



(X-2)(X+1)=(X^2-38)-(X-6)(X+6)

We move all terms to the left:

(X-2)(X+1)-((X^2-38)-(X-6)(X+6))=0

We use the square of the difference formula

X^2+(X-2)(X+1)+36=0

We multiply parentheses ..

X^2+(+X^2+X-2X-2)+36=0

We get rid of parentheses

X^2+X^2+X-2X-2+36=0

We add all the numbers together, and all the variables

2X^2-1X+34=0

a = 2; b = -1; c = +34;
Δ = b2-4ac
Δ = -12-4·2·34
Δ = -271
Delta is less than zero, so there is no solution for the equation

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